\huge \frac{-\hslash^2}{2m}\frac{d^2\psi(x)}{dx^2}+V \psi(x) = E\psi(x)
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\huge \frac{-\hslash^2}{2m}\frac{d^2\psi(x)}{dx^2}+V \psi(x) = E\psi(x)
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